Scipy (Python 的科学计算包)

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sparse

kron

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>>> from scipy import sparse
>>> A = sparse.csr_matrix(np.array([[0, 2], [5, 0]]))
>>> B = sparse.csr_matrix(np.array([[1, 2], [3, 4]]))
>>> sparse.kron(A, B).toarray()
array([[ 0, 0, 2, 4],
[ 0, 0, 6, 8],
[ 5, 10, 0, 0],
[15, 20, 0, 0]])

>>> sparse.kron(A, [[1, 2], [3, 4]]).toarray()
array([[ 0, 0, 2, 4],
[ 0, 0, 6, 8],
[ 5, 10, 0, 0],
[15, 20, 0, 0]])

$A \times B$ 如果A是一个m×n的矩阵,而B是一个p×q的矩阵,克罗内克积则是一个mp×nq分块矩阵

image-20200828144756226 image-20200828144810260

csr_matrix

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from scipy.sparse import *

row = [0,0,0,1,1,1,2,2,2]#行指标
col = [0,1,2,0,1,2,0,1,2]#列指标
data = [1,0,1,0,1,1,1,1,0]#在行指标列指标下的数字
team = csr_matrix((data,(row,col)),shape=(3,3))
print(team)
print(team.todense())

输出结果:
(0, 0) 1
(0, 1) 0
(0, 2) 1
(1, 0) 0
(1, 1) 1
(1, 2) 1
(2, 0) 1
(2, 1) 1
(2, 2) 0
[[1 0 1]
[0 1 1]
[1 1 0]]

lil_matrix

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>>> a = np.arange(100).reshape(10, 10)
>>> a
array([[ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9],
[10, 11, 12, 13, 14, 15, 16, 17, 18, 19],
[20, 21, 22, 23, 24, 25, 26, 27, 28, 29],
[30, 31, 32, 33, 34, 35, 36, 37, 38, 39],
[40, 41, 42, 43, 44, 45, 46, 47, 48, 49],
[50, 51, 52, 53, 54, 55, 56, 57, 58, 59],
[60, 61, 62, 63, 64, 65, 66, 67, 68, 69],
[70, 71, 72, 73, 74, 75, 76, 77, 78, 79],
[80, 81, 82, 83, 84, 85, 86, 87, 88, 89],
[90, 91, 92, 93, 94, 95, 96, 97, 98, 99]])

>>> lilm = scipy.sparse.lil_matrix(a)

>>> lilm[[1, 2, 3], :].toarray() # extract the rows first...
array([[10, 11, 12, 13, 14, 15, 16, 17, 18, 19],
[20, 21, 22, 23, 24, 25, 26, 27, 28, 29],
[30, 31, 32, 33, 34, 35, 36, 37, 38, 39]])

>>> lilm[[1, 2, 3], :][:, [4, 5, 6]].toarray() # ...then the columns
array([[14, 15, 16],
[24, 25, 26],
[34, 35, 36]])

安装

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sudo apt-get install python-scipy libsuitesparse-dev
pip install --user scikit-sparse

cholesky